Standard Deviation and Cash Flow Essay Sample free essay sample

Consequences from old surveies showed 79 % of all high school seniors from a certain metropolis program to go to college after graduation. A random sample of 200 high school seniors from this metropolis reveals that 162 program to go to college. Does this indicate that the per centum has increased from that of old surveies? Trial at the 5 % degree of significance. State the nothing and alternate hypotheses. A. H0: ? = . 79. H1: ? gt ; . 79 B. H0: P = . 79. H1: P ? . 79 C. H0: P ? . 79. H1: P gt ; . 79 D. H0: = . 79. H1: gt ; . 79Reset SelectionQuestion 2 of 10 1. 0 PointsSee the following scenario in replying inquiries 1 through 4. Consequences from old surveies showed 79 % of all high school seniors from a certain metropolis program to go to college after graduation. A random sample of 200 high school seniors from this metropolis reveals that 162 program to go to college. Does this indicate that the per centum has increased from that of old surveies? Trial at the 5 % degree of significance. Calculate the omega or t value of the sample trial statistic.A. z = 0. 69 B. T = 1. 645 C. z = 1. 96 D. z = 0. 62Reset SelectionQuestion 3 of 10 1. 0 PointsSee the following scenario in replying inquiries 1 through 4. Consequences from old surveies showed 79 % of all high school seniors from a certain metropolis program to go to college after graduation. A random sample of 200 high school seniors from this metropolis reveals that 162 program to go to college. Does this indicate that the per centum has increased from that of old surveies? Trial at the 5 % degree of significance. What is your decision? A. Do non reject H0. There is non adequate grounds to back up the claim that the proportion of pupils be aftering to travel to college is greater than. 79.B. Reject H0. There is adequate grounds to back up the claim that the proportion of pupils be aftering to travel to college is now greater than. 79.C. Can non find D. More seniors are traveling to collegeReset SelectionQuestion 4 of 10 1. 0 PointsSee the following scenario in replying inquiries 1 through 4. Consequences from old surveies showed 79 % of all high school seniors from a certain metropolis program to go to college after graduation. A random sample of 200 high school seniors from this metropolis reveals that 162 program to go to college. Does this indicate that the per centum has increased from that of old surveies? Trial at the 5 % degree of significance. What is the p-value associated with your trial of hypothesis?A. 0. 7563 B. 0. 6874 C. 0. 4874 D. 0. 2437Reset SelectionQuestion 5 of 10 1. 0 PointsSee the following scenario in replying inquiries 5 through 7. In an article looking in Today’s Health a author states that the mean figure of Calories in a helping of Zea mays everta is 75. To find if the mean figure of Calories in a helping of Zea mays everta is different from 75. a dietician selected a random sample of 20 helpings of Zea mays everta and computed the sample average figure of Calories per functioning to be 78 with a sample standard divergence of 7. State the nothing and alternate hypotheses. A. H0: = 75. H1: ? 75 B. H0: 75. H1: gt ; 75 C. H0: 75. H1: lt ; 75 D. H0: = 75. H1: gt ; 75Reset SelectionQuestion 6 of 10 1. 0 PointsSee the following scenario in replying inquiries 5 through 7. In an article looking in Today’s Health a author states that the mean figure of Calories in a helping of Zea mays everta is 75. To find if the mean figure of Calories in a helping of Zea mays everta is different from 75. a dietician selected a random sample of 20 helpings of Zea mays everta and computed the sample average figure of Calories per functioning to be 78 with a sample standard divergence of 7. Calculate the omega or t value of the sample trial statistic. A. z = 1. 916 B. T = -1. 916 C. T = 1. 916 D. z = 1. 645Reset SelectionQuestion 7 of 10 1. 0 PointsSee the following scenario in replying inquiries 5 through 7. In an article looking in Today’s Health a author states that the mean figure of Calories in a helping of Zea mays everta is 75. To find if the mean figure of Calories in a helping of Zea mays everta is different from 75. a dietician selected a random sample of 20 helpings of Zea mays everta and computed the sample average figure of Calories per functioning to be 78 with a sample standard divergence of 7. At the ? = . 05 degree of significance. does the dietician have adequate grounds to reject the writer’s claim? A. No B. Yes C. Can non DetermineReset SelectionQuestion 8 of 10 1. 0 PointsSee the followers in replying inquiries 8 through 10. A lab technician is tested for her consistence by taking multiple measurings of cholesterin degrees from the same blood sample. The mark truth is a discrepancy in measurings of 1. 2 or less. If the lab technician takes 16 measurings and the discrepancy of the measurings in the sample is 2. 2. does this supply adequate grounds to reject the claim that the lab technician’s truth is within the mark truth? State the nothing and alternate hypotheses. A. H0: lt ; 1. 2. H1: ? 1. 2 B. H0: ? 1. 2. H1: gt ; 1. 2 C. H0: ? 1. 2. H1: = 1. 2 D. H0: ? 1. 2. H1: ? 1. 2Reset SelectionQuestion 9 of 10 1. 0 PointsSee the followers in replying inquiries 8 through 10. A lab technician is tested for her consistence by taking multiple measurings of cholesterin degrees from the same blood sample. The mark truth is a discrepancy in measurings of 1. 2 or less. If the lab technician takes 16 measurings and the discrepancy of the measurings in the sample is 2. 2. does this supply adequate grounds to reject the claim that the lab technician’s truth is within the mark truth? Calculate the value of the appropriate trial statistic. A. T = 27. 50 B. z = 1. 65 C. = 27. 50 D. = 30. 58Reset SelectionQuestion 10 of 10 1. 0 PointsSee the followers in replying inquiries 8 through 10. A lab technician is tested for her consistence by taking multiple measurings of cholesterin degrees from the same blood sample. The mark truth is a discrepancy in measurings of 1. 2 or less. If the lab technician takes 16 measurings and the discrepancy of the measurings in the sample is 2. 2. does this supply adequate grounds to reject the claim that the lab technician’s truth is within the mark truth? At the ? = . 01 degree of significance. what is your decision?A. Do non reject H0. At the = . 01 degree of significance there is non sufficient grounds to propose that this technician’s true discrepancy is greater than the mark truth.B. Reject H0. At the = . 01 degree of significance. there is adequate grounds to back up the claim that this technician’s discrepancy is larger than the mark truth. C. Can non find D. Reject H0. At the = . 01 degree of significance. there is non adequate grounds to back up the claim that this technician’s true discrepancy is larger than the mark truth.